The bob of a pendulum is released from a horizontal position A as shown in figure. If the length of the pendulum is 2 m, what is the speed with which the bob arrives at the lowermost point B, given that it dissipated 10% of its initial potential energy w.r.t. B point against air resistance? (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(6 m s –1 )
Sol. W g + W R = Δ K
mgl – 0.1 mg λ = 
mv 2
v = 
= 
= 6 m/s –1 .
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